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Which of the following compound would show optical isomerism?
a) CH3 – CH(OH) COOH
b) H2N CH(CH3)2
c) (CH3)2 CHCHO
d) H2N CH2 COOH?
Most Upvoted Answer
Which of the following compound would show optical isomerism?a) CH3 – ...
Explanation:

Definition of Optical Isomerism:
Optical isomerism is a form of stereoisomerism where compounds have the same molecular formula and sequence of bonded atoms but differ in the three-dimensional arrangement of their atoms in space, resulting in non-superimposable mirror images.

Identification of Compound Showing Optical Isomerism:
- a) CH3 – CH(OH) COOH: This compound contains a chiral carbon atom bonded to four different groups (H, C, OH, COOH), which allows for optical isomerism.
- b) H2N CH(CH3)2: This compound does not contain a chiral carbon atom as the nitrogen is attached to two methyl groups and a hydrogen atom, making it achiral.
- c) (CH3)2 CHCHO: This compound does not have a chiral carbon atom as the carbonyl group is bonded to two methyl groups, resulting in an achiral compound.
- d) H2N CH2 COOH: This compound contains a chiral carbon atom bonded to two different groups (H, COOH) and two identical hydrogen atoms, which does not allow for optical isomerism.

Conclusion:
The compound that would show optical isomerism is a) CH3 – CH(OH) COOH as it contains a chiral carbon atom with four different groups attached, fulfilling the requirements for optical isomerism.
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Which of the following compound would show optical isomerism?a) CH3 – CH(OH) COOHb) H2N CH(CH3)2c) (CH3)2 CHCHOd) H2N CH2 COOH?
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