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Which of the following compound would show optical isomerism?
a) CH3 – CH(OH) COOH
b) H2N CH(CH3)2
c) (CH3)2 CHCHO
d) H2N CH2 COOH?
a) CH3 – CH(OH) COOH
b) H2N CH(CH3)2
c) (CH3)2 CHCHO
d) H2N CH2 COOH?
Most Upvoted Answer
Which of the following compound would show optical isomerism?a) CH3 – ...
Explanation:
Definition of Optical Isomerism:
Optical isomerism is a form of stereoisomerism where compounds have the same molecular formula and sequence of bonded atoms but differ in the three-dimensional arrangement of their atoms in space, resulting in non-superimposable mirror images.
Identification of Compound Showing Optical Isomerism:
- a) CH3 – CH(OH) COOH: This compound contains a chiral carbon atom bonded to four different groups (H, C, OH, COOH), which allows for optical isomerism.
- b) H2N CH(CH3)2: This compound does not contain a chiral carbon atom as the nitrogen is attached to two methyl groups and a hydrogen atom, making it achiral.
- c) (CH3)2 CHCHO: This compound does not have a chiral carbon atom as the carbonyl group is bonded to two methyl groups, resulting in an achiral compound.
- d) H2N CH2 COOH: This compound contains a chiral carbon atom bonded to two different groups (H, COOH) and two identical hydrogen atoms, which does not allow for optical isomerism.
Conclusion:
The compound that would show optical isomerism is a) CH3 – CH(OH) COOH as it contains a chiral carbon atom with four different groups attached, fulfilling the requirements for optical isomerism.
Definition of Optical Isomerism:
Optical isomerism is a form of stereoisomerism where compounds have the same molecular formula and sequence of bonded atoms but differ in the three-dimensional arrangement of their atoms in space, resulting in non-superimposable mirror images.
Identification of Compound Showing Optical Isomerism:
- a) CH3 – CH(OH) COOH: This compound contains a chiral carbon atom bonded to four different groups (H, C, OH, COOH), which allows for optical isomerism.
- b) H2N CH(CH3)2: This compound does not contain a chiral carbon atom as the nitrogen is attached to two methyl groups and a hydrogen atom, making it achiral.
- c) (CH3)2 CHCHO: This compound does not have a chiral carbon atom as the carbonyl group is bonded to two methyl groups, resulting in an achiral compound.
- d) H2N CH2 COOH: This compound contains a chiral carbon atom bonded to two different groups (H, COOH) and two identical hydrogen atoms, which does not allow for optical isomerism.
Conclusion:
The compound that would show optical isomerism is a) CH3 – CH(OH) COOH as it contains a chiral carbon atom with four different groups attached, fulfilling the requirements for optical isomerism.
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Which of the following compound would show optical isomerism?a) CH3 – CH(OH) COOHb) H2N CH(CH3)2c) (CH3)2 CHCHOd) H2N CH2 COOH?
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Which of the following compound would show optical isomerism?a) CH3 – CH(OH) COOHb) H2N CH(CH3)2c) (CH3)2 CHCHOd) H2N CH2 COOH? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Which of the following compound would show optical isomerism?a) CH3 – CH(OH) COOHb) H2N CH(CH3)2c) (CH3)2 CHCHOd) H2N CH2 COOH? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following compound would show optical isomerism?a) CH3 – CH(OH) COOHb) H2N CH(CH3)2c) (CH3)2 CHCHOd) H2N CH2 COOH?.
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